NCHMCT JEE Exam Pattern 2026

Hi Srija

Yes, we have the previous year's question papers for you to practice for the NCHMCT JEE exam . Click on the link below to access and download the question papers.

• NCHMCT JEE Question Papers

Hi Ritesh
Here is the article for your reference
https://hospitality.careers360.com/articles/best-books-for-nchmct-jee-preparation

Hello,

The NCHM JEE 2026 registration is expected to start in the second week of December 2025 .
The application form will be available online.
The last date to apply will likely be February or March 2026 .

The exact dates will be announced in the official notification.

Hope it

Hy,

In Patna, several colleges offer B.Ed programs and provide facilities such as girls' hostels. Here are a few notable institutions:

1. Patna University

• Institute : Department of Education
• Girls’ Hostel : Available

2. Magadh University

• Institute : Various affiliated colleges offer B.Ed programs.
• Girls’ Hostel : Available in some

Hello John,

With an AIR of 586 in NCHM-JEE, you have a reasonable chance of getting into IHM Pusa, especially if the past cutoffs were around 200-400. Your rank is competitive, and while IHM Pusa is one of the top institutes, there might still be a possibility of admission depending

Dear

According to the information in the NCHM-JEE Exam , you are not required to attempt all questions . The exam consists of 200 questions , and you can attempt as many questions as you like within the given time limit of 3 hours . There is no limit on

Correct Answer: 7 : 3

Solution : Given: $21 \tan \theta=20$
⇒ $\tan \theta = \frac{20}{21}=\frac{\text{Perpendicular}}{\text{Base}}$
Let the perpendicular and the base be 20 units and 21 units respectively.
Use the formulas,
$\tan \theta=\frac{\text{Perpendicular}}{\text{Base}}$,
$\sin \theta=\frac{\text{Perpendicular}}{\text{Hypotenuse}}$,
$\cos \theta=\frac{\text{Base}}{\text{Hypotenuse}}$,
Pythagoras's theorem: $\text{Hypotenuse}^2=\text{Base}^2+\text{Perpendicular}^2$
⇒ $\text{Hypotenuse}^2={21}^2+{20}^2$
⇒ $\text{Hypotenuse}^2=441+400$
⇒ $\text{Hypotenuse}^2=841$
⇒ $\text{Hypotenuse}=\sqrt{841}$
⇒

hlwo aspirant

hope you are doing well

there are chances of getting placements after Diploma. It depends on your course and College. But, For better career opportunities you can choose to go with higher studies since most of the IT companies prefer BE graduates.

let's take a assumption that your

Hello Aspirant,

For different sections, books of NCHM JEE are enlisted below :-

@English Language

Arihant General English for all Competitive Examinations (English) by Hari Mohan Prashad

Pearson’s English

High School English Grammar & Composition Revised Edition (English) 1st Edition by Wren and Martin

@Numerical Ability & Scientific Aptitude

Quantitative

Hello,

Allahabad University (AU) will release the admit card of LAT 2022 tentatively by last week of July 2022. LAT 2022 admit card will be available for download on the official admission portal of the university. The officials have not yet released the exact date. Keep an eye on the